GPS location from image to determine
By following script can read the GPS data from JPEG files.
Sunday, August 29, 2010
Pokemon Monopoly 2009
It generates not only the pure issue of the coordinates and a helpful Google Maps link. PICTURE WAS TAKEN AT ==================
LON: -86.88650000
LAT: 41.73200000 LON: -86.88650000
GOOGLE MAPS LOCATION ============== ==== http://maps.google.com/?q=41.73200000,-86.88650000 #!/usr/bin/python
import sys from PIL import Image # Florian Roth
# PictureDelphi 0.1
# August 2010 # PictureDelphi 0.1
from PIL.ExifTags import TAGS
def get_exif(fn):
ret = {}
i = Image.open(fn)
try:
info = i._getexif()
for tag, value in info.items():
decoded = TAGS.get(tag, tag)
if decoded == "GPSInfo":
ret["GPSInfo"] = value
lat_t = ret["GPSInfo"][1]
lon_t = ret["GPSInfo"][3]
lat = float(ret["GPSInfo"][2][0][0])
lat_add = float( ret["GPSInfo"][2][1][0] )
lat_add = lat_add/60/100
lat = lat+lat_add
if lat_t == "S":
lat *= -1;
lon = float(ret["GPSInfo"][4][0][0])
lon_add = float( ret["GPSInfo"][4][1][0] )
lon_add = lon_add/60/100
lon = lon+lon_add
if lon_t == "W":
lon *= -1;
print "PICTURE WAS TAKEN AT =================="
print "LON:% .8 f '% lon
print" LAT:% .8 f "% lat
" print GOOGLE MAPS LOCATION =================="
print "http://maps.google.com/?q = f% .8, .8% f"% (lat, lon);
except:
print "No GPS data present in the picture meta data"
foto = sys.argv [1]
get_exif (photo)
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